Use benchmarks to estimate the sum, difference, or pruduct. 14/16 + 1/5

A. 2

B. 0

C. 1/2

D. 1


7 1/7 - 1 9/10

A. 9

B. 4

C. 5

D. 6


Use benchmarks to estimate the sum, difference, or product

7 2/7 x 3 7/9

A. 32

B. 28

C. 24

D. 21


Find the sum

3/9 + 4/9

A. 7/9

B. 7/18

C. 7/81

D. 2/3


-3/4 + 15/24

A. -3/4

B. 1/2

C. 1/8

D. -1/8


12 1/9 + 10 2/3

A. 22 1/6

B. 22 7/9

C. 22 1/9

D. 22 1/4


-1/5 + (-3/7

A. -22/35

B. - 1/3

C. 12/35

D. 4/7

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

oof cheaters cheat because they’re lazy that’s why i cheat xd

: )

step-by-step explanation:

its a straight line parallel to the time axis