The function h(0) = -16t2 + vt + 10 gives the height of a platform diver above the water, in feet, t seconds after

It will take t = 0.3125 seconds is the diver's height above the water 15 feet.

Given ,

The height of a diver jumping from a diving platform is h

 h(t) =

The diver's height above the water 15 feet

Velocity = v = 11 ft per second

We have to find, t seconds is the diver's height above the water 15 feet.

According to the question,

Where v = 11, h(t) = 15

15 = -16 + 11t + 10  

15 - 10 =

5 =

16t ( t - 1 ) - 5 ( t + 1 ) = 0

(16t - 5 ) ( t + 1 ) = 0

16t - 5 = 0

16t = 5

t =

t = 0.3125

And t + 1 = 0

t = -1

Time can not be negative so we can't take t = -1 .

So, The required value of time is t = 0.3125

Hence, it will take t= 0.3125 seconds is the diver's height above the water 15 feet.

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Complete Question:

The height of a diver jumping from a diving platform is about , where h is the height of the diver in feet above the water and t is the time measured in seconds, when diving from a platform about 34.3 feet above the water with an upward initial velocity of 11 ft/sec..  After how many seconds is the diver's height above the water 15 feet?

0.3125 seconds

Step-by-step explanation:

Given

Required

Time when the diver is above 15ft

This implies that h(t) = 15

So, we have:

Collect Like Terms

Expand:

Factorize:

Split

or

or

Solve for t

or

or

But time can't be negative. So:

Hence, it will take the diver 0.3125 seconds to be at a height above 15 feet

8/k

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