Solve the given system. x = 10 + y
y = 6x + 5

I need some help with this particularly on how to solve systems

x = -3

y = -13

Step-by-step explanation:

There are many ways you can solve these types of questions:

x = 10 + y ... 1

y = 6x + 5 ... 2

You can sub y = 6x + 5 into the first equation

Hence, x = 10 + 6x + 5

Simplify

-5x = 15

x = -3  ===> sub this value into any equation ...1 or ...2 (I'm going to go with 1)

-3 = 10 + y

-3 - 10 = y

y = -13

Another way: Rearrange the first equation so that it would be y = x - 10

Then the two equations would be:

y = x - 10 ... 3

y = 6x + 5 ... 4

Since they both equal y and y has to be the same value, these two equations would equal each other.

Hence, x - 10 = 6x + 5

Rearrange: x - 6x = 5 + 10

-5x = 15

x = -3

Sub the value of x into 3 or 4 and you would get y = -13

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.

show da graph

step-by-step explanation: