The weights, in pounds, of the cats in an animal adoption center are normally distributed. If a random sample of cats is taken and the confidence interval is (7.9,12.7), what is the margin of error? Give a numerical response for your answer. For example, if you found that the margin of error was 2, you would enter 2.

2.4

Step-by-step explanation:

Given that :

The confidence interval = ( 7.9 , 12.7 )

The Margin of error M.O.E = Interval width/2

where;

The interval width = UCL - LCL

The interval width = 12.7 - 7.9

The interval width = 4.8

∴

The Margin of error M.O.E = 4.8/2

The Margin of error M.O.E = 2.4

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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b.-4 units

all you   do is count how many times you move