Mathematics, 19.11.2020 18:40 ktprada
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Todd draws a diagram using four identical right triangles to form a square as shown. Which BEST describes how to use the areas of the shaded triangles to begin a proof of the Pythagorean theorem?
(It does not come with a picture!!)
A. The side length of the white square is A, so the combined are of the four right triangles is C to the power of 2 mines A to the power of 2. This is equivilent to four times the area of each triangle. So, C to the power of 2 mines A to the power of 2 equals 4 (1/2 ab)
B. The side length of the white square is A, so the combined are of the four right triangles is C to the power of 2 mines A to the power of 2. This is equivalent to the area of each triangle. So, C to the ower of 2 mines A to the power of 2 equals 1/2ab
C. The side length of the white square is B - A, so the combined are of the four right triangles is C to the power of 2 mines ( B - A) to the power of 2. This is equivilent to four times the area of each triangle. So, C to the power of 2 mines (B - A) to the power of 2 equals 4 (1/2ab).
D. The side length of the white square is B - A, so the combined are of the four right triangles is C to the power of 2 mines B to the power of 2. This is equivalent to the area of each triangle. So, C to the power of 2 mines B to the power of 2 equals 1/2 ab.
Answers: 2
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Given the system of equations presented here: 2x + 4y = 14 4x + y = 20 which of the following actions creates an equivalent system such that, when combined with the other equation, one of the variables is eliminated? multiply the second equation by â’4 to get â’16x â’ 4y = â’80 multiply the second equation by â’1 to get â’4x â’ y = â’20 multiply the first equation by 2 to get 4x + 8y = 28 multiply the first equation by â’1 to get â’2x â’ 4y = â’14
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Todd draws a diagram using four identical right triangles to form a squa...
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