Find the component form of the vector that translates P(4,5) to P'. P'(-3, 7) P'(-1,-6)

We start with the point P(4,5) and this is translated to the point P'(a, b).

We want to find the component form of the vector associated with the translation.

For a general translation for a point: P = (p1, p2) to Q = (q1, q2)  the components of the vector will be:

V = < (q1 - p1), (q2 - p2)>

Then, if the points are:

1) P(4, 5) and P'(-3, 7)

The vector is:

V = < (-3 - 4), (7 - 5) > = <-7, 2>

2) P(4, 5) and P'(-1, - 6)

The vector is:

V = < (-1 - 4), (-6 - 5)> = <-5, -11>

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb

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