The length of the floor is 32 m longed than it’s witdth and there is greater than 200 square meters. You will cover the floor completely with tiles. what will be the possible dimension of the floor? with solution po sana ty p

Step-by-step explanation:

The area of the floor A = Length * Width

Given

A = 200 square meters

If the length of the floor is 32 m longed than it’s width then;

L = 32+W

A = LW

200 = (32+W)W

200 = 32W + W²

W²+32W-200 = 0

W = -32±√32²+800/2

W = -32±42.71/2

W =  -32+42.71/2

W = 10.71/2

W = 5.35 m

L = 32+5.35

L = 37.35m

Hence the dimension is  5.35ft by 37.35m

b. -7,185,024p6q5

step-by-step explanation:

find the 6th term of the expansion of (2p - 3q)11. a. -7,185,024p4q7 c. -7,185p4q7 b. -7,185,024p6q5 d. -7,185p6q5 select the best answer from the choices provided a b c d

he has now walked a total of what?

if i know what this is maybe i can

step-by-step explanation: