Mathematics, 19.11.2020 06:40 hurricane01

A manufacturer wants to produce an ice cream cone with the same volume and diameter of a spherical scoop of ice cream 6cm in diameter. What should the height of the cone be?

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Answer from: dozsyerra

IS THIS NIKHIL GARG?!?!?!?!?!? THE FORTNITE PRO?!?!?!?!?!?!??!?!?!?

Step-by-step explanation:

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Answer from: heavyhearttim

HEY NIKHIL GARG MR. FORTNITE BATTLE ROYALE THE ANSWER IS 12

Step-by-step explanation:

TRUST BRO IF THE HEIGHT IS 12 THEN ITLL HAVE THE SAME VOLUME AS THE SPHERE, WHICH IS 36 PI

Answer from: Quest

answer: the answer is 110

Answer from: Quest

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.