3.
Solve tan 2x + tan x=0, for 0 < x < 2π

Start by getting everything on the same side of the equals sign and then set it equal to 0.  .  Factor out the common tan^2x like this: .  Now we have 2 separate equations to solve:  and sinx = 0.  Now we have to figure out where tan^2 is 0 between 0 and 2pi.  If we include 2pi, the solutions for that equation are .  You can test those out on your calculator just to be sure.  There's only one value of x for the next equation.  The only place between 0 and 2pi where the sin x = 1 is at x = .  And there you go!

Step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v