Noise levels at 3 airports were measured in decibels yielding the following data: 108,146,160

Required:
a. Construct the 90% confidence interval for the mean noise level at such locations. Assume the population is approximately normal.
b. Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.

a)  The 90% confidence interval for the mean noise level at such locations      

  (112.46 , 163.54)

b) The critical value that should be used in constructing the confidence interval

Z₀.₁₀ = 1.645

Step-by-step explanation:

Step(i) :-

Noise levels at 3 airports were measured in decibels yielding the following data

108   146   160

Mean of given data

x          :     108   146   160

x-x⁻      :      -30   8       22

(x-x⁻ )² :     900   64     484

Variance  σ ² = ∑(x-x⁻ )²/ n-1

                                        =

Standard deviation  

                σ = √724 = 26.90

Step(ii):-

The 90% confidence interval for the mean noise level at such locations                        

The critical value that should be used in constructing the confidence interval

Z₀.₁₀ = 1.645

        ( 138 - 25.54 , 138 + 25.54 )

        (112.46 , 163.54)

54

step-by-step explanation:

total amount of money that he should pay if he has not used his duty free exemption is $98

step-by-step explanation:

given a united states citizen returning to the states declares the following items at the customs office: 3 shirts at $8.50 each 2 dresses at $27.50 each 1 pair of gold cuff links at $17.50 per pair. we have to find how much he pay

cost of 3 shirts if one cost at $8.50 is

cost of 2 dresses if one cost at $27.50 is  

cost of 1 pair of gold cuff at $17.50

so, total amount of money that he should pay if he has not used his duty free exemption is   $25.5+$55+$17.50=$98