Juan decided to start saving for college. He deposited $500 into an account which earns 4% simple annual interest. At the end of each year, he will add $250 to this account. How much will he have in his account after the end of three years?

$5504

Step-by-step explanation:

Given that :

Principal amount = $500

Interest = 4% simple interest annually

Amount added at the end of each year :

First year:

Principal + (Principal * rate * time)

500 + (500 * 0.04) = 520

$520 + $250 = $770

2nd year:

770 + (770 * 0.04) = $800.80

$800.80 + $250 = 1050.80

3rd year:

1050.8 + (1050.8 * 4) = 5254

$5254 + 250 = $5504

answer: 2x + 2 − 2 = 10 − 2; subtraction property of equality

step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!