14 black balls and 6 white balls are placed in an urn. Two balls are then drawn in succession. What is the probability that the second ball drawn is a white ball if the second ball is drawn without replacing the first ball?a) 0.3333 b) 0.2381
c) 0.0952
d) 0.2143
e) 0.3111

The probability that the second ball drawn is a white ball if the second ball is drawn without replacing the first ball is 0.33.

Given :

The formula given below can be used in order to determine the probability that the second ball drawn is a white ball if the second ball is drawn without replacing the first ball.

Now, substitute the values of known terms in the above formula.

Simplify the above expression.

P = 0.33

So, the probability that the second ball drawn is a white ball if the second ball is drawn without replacing the first ball is 0.33.

Therefore, the correct option is a).

For more information, refer to the link given below:

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Step-by-step explanation:

Given

Represent Black with B and White with W

Required

Probability of the second selection being white

This means that: The first selection could be white or black but the second must be white.

This probability would be represented as thus:

And it is calculated as:

Notice that, the second selection has total -1 has its denominator. This is so because, the first selection was made without replacement

So, the formula becomes

22 dimes and 9 nickels

step-by-step explanation:

answer is because 4×10=40

and 98×4= is 392

40,392