The scores on two standardized tests are normally distributed. The first test had a mean of 58 and a standard deviation of 6. The second test had a mean of 78 and a standard deviation of 5. What score would you need on the second test to equal a score of 66 on the first test? Give answer to the nearest whole number.

84.67

Step-by-step explanation:

Given that :

First test:

Mean (m) = 58

Standard deviation (s) = 6

A score of 66 on the first test :

Z score (standardized score) :

Z = (66 - 58) / 6

Zscore = 1.3333

Second test:

Mean (m) = 78

Standard deviation (s) = 5

Using the Zscore pertaining to 66 in the first test :

Z = (x - m) / s

1.3333 = (x - 78) / 5

1.3333 * 5 = x - 78

6.66667 = x - 78

x = 6.6667 + 78

x = 84.67

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !

3030 ur welcome

step-by-step explanation: