What is the slope of a line perpendicular to the line whose equation is 10x+ 6y = -84. Fully reduce your answer.

Step-by-step explanation:

If the lines are perpendicular, then the slopes have the same absolute value, but opposite signs. So, to find the slope of the perpendicular, we first have to find the slope of line whose equation is 10x + 6y = -84. To do this, we'll convert the equation into slope-intercept form by isolating y:

10x + 6y = -84

6y = -84 - 10x

y = -84/6 - 10x/6

y = -14 - x

10/6 can be simplified to 5/3:

y = -x - 14

The slope of the first equations line is -5/3. So, the slope of the line perpendicular to this line is 5/3.

3/5

Step-by-step explanation:

10x + 6y = -84

6y = -84 - 10x

y = -14 - 5/3x

since the two lines are perpendicular, the products if their slope = -1

hence,

-5/3 x slope of the other line = -1

slope of the other line = 3/5

Topic: coordinate geometry

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it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: