What values of b will cause 8x^2 x bx + 2 = 0 to have one real solution?

Explanation:

I'm assuming you meant to type 8x^2 + bx + 2 = 0

Compare this to ax^2 + bx + c = 0

We have a = 8, b = unknown, c = 2.

We'll use the discriminant formula which is D = b^2 - 4ac to find that

D = b^2 - 4ac

D = b^2 - 4*8*2

D = b^2 - 64

Since we want one real solution, we set the discriminant equal to zero.

D = b^2 - 64

0 = b^2 - 64

64 = b^2

b^2 = 64

b = sqrt(64) or b = -sqrt(8)

b = 8 or b = -8

So the equation 8x^2 + 8x + 2 = 0 has one solution. So does the equation 8x^2-8x+2 = 0

343t464564435rri76i6u

step-by-step explanation:

because i said it is