Mathematics, 18.11.2020 07:20 savannahvargas512

Ort each equation according to whether it has one solution, infinitely many solutions, or no solution -3(X - 4) = – 3x + 12
4(x + 1) = 3x + 4
-2(x-3) = 2x - 6
6(x + 5) = 6x + 11
5(x-2)=5x-7

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Ort each equation according to whether it has one solution, infinitely many solutions, or no solution -3(X - 4) = – 3x + 124(x + 1) = 3x + 4-2(x-3) = 2x - 66(x + 5) = 6x + 115(x-2)=5x-7

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Ort each equation according to whether it has one solution, infinitely many solutions, or no solution -3(X - 4) = – 3x + 12
4(x + 1) = 3x + 4
-2(x-3) = 2x - 6
6(x + 5) = 6x + 11
5(x-2)=5x-7