Consider the growth function f(x)=200(1.08). Describe the characteristics of the functions by using the drag and drop feature

1) Domain: -∞ < x < +∞

2) Range: y > 0

3) y intercept: (0, 200)

4) Asymptote: y = 0

5) The growth rate; r = 0.08

6) The growth factor = 1.08

7) End Behavior: As x → -∞, f(x) → 0

8) End Behavior: As x → +∞, f(x) → +∞

Step-by-step explanation:

1) The domain of the function is given as the x values for which the function is valid which includes from -∞ < x  to +∞

2) The range of the function, are the range of the output values of the function for the given range of the input values

For the function, f(x) = 200·(1.08)ˣ, we have, f(x) = y > 0, for all values of x

3) The y-intercept is the value of y, when x = 0, given as follows;

y intercept = f(0) = 200·(1.08)⁰ = 200 × 1 = 200

4) The asymptote is the line that the function approaches but never reaches

In the question, as x tends to -∞, the function f(x) approaches 0. Therefore, f(x) = y = 0 is the asymptote of the function

5) The growth rate of an exponential function, y = a(1 + r)ˣ is r

Therefore, for the function, 200·(1.08)ˣ, which is equivalent to 200·(1 + 0.08) ˣ, the growth rate = 0.08

6) The growth factor of an exponential function, y = a(1 + r)ˣ is (1 + r)

Therefore, for the function, 200·(1.08)ˣ, which is equivalent to 200·(1 + 0.08) ˣ, the growth factor = (1 + 0.08) = 1.08

7) The end behavior as x tends to -∞,

8) The end behavior as x tends to +∞,

answer: approximately 206 bones

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