(c) is a circle of center O and radius R=2 cm, and A is a point such that OA=3 cm. There exist two circles of center A and tangent to (c). Construct these circles; calculate their radii

Given :

C) is a circle of center O and radius R=2 cm, and A is a point such that OA=3 cm.

There exist two circles of center A and tangent to (C).

To Find :

The radius of the new circles.

Solution :

Since, OA is 3 cm .

So, first circle with tangent to C if centre is at A is OA itself.

First radius, r = 3 cm.

And second circle is the on with radius , R = 3 + 2 = 5 cm.

Therefore, the radius of both the circles are 3 cm and 5 cm.

Hence, this is the required solution.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

i use my brain for prombles like this maybe you could try it

step-by-step explanation: