A newly planted tree will be secured by wires, each attached to the ground 1.5 meters from the base of the tree. If each wire is 4 meters long, how high up the tree should each wire be attached, to the nearest tenth of a meter?

3.7m

Step-by-step explanation:

The set up will form of right angled triangle with;

the length of the wires (the hypotenuse) = 4m

The base of the tree from the wire (adjacent) = 1.5m

The height of the tree(opposite ) = x

According to pythagoras theorem;

hyp² = opp²+adj²

4² = x²+1.5²

16 = x²+2.25

x² = 16 - 2.25

x² = 13.75

x = √13.75

x = 3.708

Hence the tree is 3.7m high (to the nearest tenth)

a - base

b - exponent

so,

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic