An air traffic controller is tracking two planes. To start, Plane A was at an altitude of 1200 meters, and Plane B was at an altitude of 816 meters. Plane A is gaining altitude at 10 meters per second, and Plane B is gaining altitude at 18 meters per
second.
Let x be the number of seconds that have passed.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

correct answer is c. just did it

step-by-step explanation:

6 and 24

step-by-step explanation:

6 x 4 = 24