Graph a line that contains the point (-2,7) and has a slope of 4 help plz !!!

Find the Equation with a Point and Slope  of 4

Find the value of b using the formula for the equation of a line.

Use the formula for the equation of a line to find b.

y = mx + b

Substitute the value of m into the equation.

y = (4) ⋅ x + b

Substitute the value of x into the equation.

y = (4) ⋅ (−2) + b

Substitute the value of y into the equation.

7 = (4) ⋅ (−2) + b

Find the value of b.

Rewrite the equation as (4) ⋅ (−2) + b = 7. (4) ⋅ (−2) + b = 7  

Multiply 4 by −2.

−8 + b = 7

Move all terms not containing b to the right side of the equation.

Add 8 to both sides of the equation.

b = 7 + 8

Add 7 and 8.

b = 15

Now that the values of m (slope) and b (y-intercept) are known, substitute them into y = mx + b

to find the equation of the line.

y = 4x + 15

< 4, -5>

step-by-step explanation:

starting from g. we move 4 right and then 5 down to get to h. that means the vector is < 4, -5>

answer: expected value of x = 1.0

step-by-step explanation:

p(x=0) = 0.25

p(x=1) = 0.50

p(x=2) = 0.25

expected value for x = 0×0.25 + 1×0.5 + 2×0.25 = 1.0