PLEASE HELP
solve 2v^2+4v=6 by factoring.

v = 1 or -3

Step-by-step explanation:

2v^2 + 4v = 6

take 2 as common

2(v^2 + 2v = 3)

v^2 + 2v = 3

Now,

v^2 + 2v - 3 = 0

v^2 - v + 3v - 3 = 0

v(v - 1) + 3(v - 1) = 0

(v - 1) (v + 3) = 0

v = 1 or -3

21

step-by-step explanation:

11279

yes the total will be same because in both of them the expression.is rearranged but their sign remains the same hence it hss just been shuffled