f of x equals 4 x over quantity x squared minus 16. Show all work to identify the asymptotes and zero of the function.

Given:

The function is

To find:

The asymptotes and zero of the function.

Solution:

We have,

For zeroes, f(x)=0.

Therefore, zero of the function is 0.

For vertical asymptote equate the denominator of the function equal to 0.

Taking square root on both sides, we get

So, vertical asymptotes are x=-4 and x=4.

Since degree of denominator is greater than degree of numerator, therefore, the horizontal asymptote is y=0.

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation:

666666666666666666666

6

6

6

6

6

6

6

66

6

6

6

66

6

66answer:

step-by-step explanation: