The probability of a basketball player making a free throw is 76%. In practice she shoots 10 free throws. What is the probability that he makes 7 free throws?

0.243

Step-by-step explanation:

Given that :

Probability of success (p) = 76% = 0.76

Number of free throws (n) = 10

Probability of making 7 free throws = r

Using binomial distribution :

nCr * p^r * (1 - p)^(n-r)

10C7 * 0.76^7 * (1 - 0.76)^(10 - 7)

10C7 * 0.76^7 * 0.24^3

120 * 0.14645 * 0.013824

= 0.24294

Hence probability of making 7 free throws from 10 is 0.243

right

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.