Given the equation 3x + 4y = 10, select a second equation that would create a system with no solutions. 3x + 4y = -10

3x - 4y = 10

3x + 4y = 10

3.x - 4y = -10

3x + 4y = -10

Step-by-step explanation:

Here, we want to select which of the options will give a system of two equations coupled with the first such that we have no solutions

Since we already have 3x + 4y = 10

The equation that will give a system leading to no solutions will be a system that equates the exact sum of 3x + 4y to another value

Mathematically, that will be;

3x + 4y = -10

my guess would be b and d, but i didn’t actually get out the pen and paper. lol

hi there!

question 1 answer: p/q can be terminating when q = 5^m * 2^n

question 2 answer: -1 and -1

question 3 answer: -4

question 4 answer: 5/12

hope this : )