2 1
6. In Fig. 13.29, the congruent parts are marked
Prove that ABAC = ACDB.
A
В.
С
D
Fig. 13.29
7. In Fig. 13.30, ABC is an equilateral triang
and AD is perpendicular to BC. Prove th
AADB = AADC in three different ways.
A
B D
C С
Fig. 13.30
r
.
12
in the hisen

step-by-step explanation:

infinity is the answer

given : the shape of his satellite can be modeled by   where x and y are modeled in inches.

now,the given equation   is a equation of parabola.

here, coefficient of x is positive, hence the parabola opens rightwards.

on comparing this equation with standard equation , we get

in standard equation, coordinates of focus=(0,m)

thus for given equation coordinates of focus=(0,1.5)

step-by-step explanation: