A racecar driver is doing a time trial of a new car on a straight back. The car's distance from the timekeeper is represented by y=293x+50 where x is time in seconds and y is the distance from the timekeeper's position. How many feet from the timekeeper is the race car at the beginning?

50 feet

Step-by-step explanation:

The car's distance from the timekeeper us given by :

y = 293x+50

Where x is time in seconds and y is the distance from the timekeeper's position.

The general equation of a line is given by :

y = mx +c

On comparing, we get : c = 50

It means the timekeeper has covered 50 feets at the beginning.

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.