Find the equation of the line that - is perpendicular to the line y=3x-1
and
-passes through the point (7,4)

y = -1/3x + 19/3

Step-by-step explanation:

let the equation of the line be y = mx + b

since it is perpendicular to y = 3x - 1, these two lines's gradient when producted gives -1.

hence, 3 x m = -1

m = -1/3

sub m = -1/3 and (7, 4):

4 = -1/3(7) + b

b = 19/3

therefore, equation of the line is y = -1/3x + 19/3

Topic: coordinate geometry

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b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right

step-by-step explanation:

infinity is the answer