Mathematics, 15.11.2020 14:00 janeou17xn
Mrs. Culland is finding the center of a circle whose equation
is x2 + y2 + 6x - 4y – 3 = 0 by completing the square. Her
work is shown.
x2 + y2 + 6x + 4y - 3 = 0
x2 + 6x + y2 + 4y - 3 = 0
(x2 + 6x) + (12 + 4y) = 3
(x2 + 6x + 9) + (y2 + 4y + 4) = 3 + 9 + 4
Which completes the work correctly?
(x - 3)2 + ( - 2)= 42, so the center is (3,2).
(x + 3)2 + (y + 2)2 = 42, so the center is (3, 2).
(x - 3)2 + (x - 2)2 = 42, so the center is (-3,-2).
(x + 3)2 + (y + 2)2 = 42, so the center is (-3, -2).
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Mrs. Culland is finding the center of a circle whose equation
is x2 + y2 + 6x - 4y – 3 = 0 by compl...
Mathematics, 08.07.2019 16:20