Simplify the expression:
(x^3y^n/z^m+1)^k

3yxnzmk/z+ k, I’m pretty this is it since there were no other numbers:)

Answer to your question: a. the fundamental theorem of algebra tells you that the equation will have two complex roots since the degree of the polynomial is 2. the roots are ​ x=1±i7√2 .number of roots=degree of polynomialhere, degree of polynomial is 2 so number of roots will be 2.hope it *_*