What is the vertex of the graph of the function f(x) = x^2 + 8x − 2 ? (−4, 18)
(0, -2)
(-8, -2)
(−4, −18)

The vertex is at (-4, -18)  (Fourth answer choice)

Step-by-step explanation: The standard vertex equation of a parabola is f(x) = (x - h)^2 + k.

"Completing the square" is one of the faster and better ways of determining the vertex:

f(x) = x^2 + 8x - 2  =>  f(x) = x^2 + 8x + 16 - 16 - 2  =>  (x + 4)^2 - 18.  Comparing this to (x - h)^2 + k, we see that h = -4 and k = -18.  The vertex is at (-4, -18).

step-by-step explanation:

you divide the denominator by the numerator on both sides and if the quotients are equal then the fractions are equivalent