The list shows the number of songs that five students each downloaded last week. 32, 43, 38, 28, 51
What is the mean absolute deviation of the numbers in the list?
F 34.4
G 6.88
H 38.4
J 7.68

g)6.88

Step-by-step explanation:

We’ll begin by finding the mean of the data set.

32+43+38+28+51=192      then 192/5=38.4

Then find the absolute value of the difference between each data value and the mean.

l32-38.4l=6.4

l43-38.4l=4.6

l38-38.4l=0.4

l28-38.4l=10.4

l51-38.4l=12.6

Lastly, find the sum of the absolute values and divide by the number of the values

6.4+4.6+0.4+10.4+12.6=34.4

34.4/5=6.88

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.