A plane traveled 336 miles to Carson City and back. The trip there was with the wind. It took 4 hours. The trip back was into the wind. The trip back took 6 hours. What is the speed of the plane in still air? What is the speed of the wind?

Thus, train speed = 70 mph while wind speed is. y = 14 mph

Step-by-step explanation:

Let x = speed of the plane in mph.

Let y = speed of wind in mph.

We are told that The trip there was with the wind. It took 4 hours. The trip back was into the wind. The trip back took 6 hours.

Formula for distance is;

Distance = speed × time

Thus;

(x + y)4 = 336

(x + y) = 84 - - - - (1)

Also;

(x - y)6 = 336

Divide both sides by 6

(x - y) = 56 - - - (eq 2)

Add eq 1 and 2 to give;

2x = 84 + 56

2x = 140

x = 140/2

x = 70 mph

Plug in 70 mAh for x in eq 1.

(70 - y) = 56

y = 70 - 56

y = 14 mph

Thus, train speed = 70 mAh while wind speed is. y = 14 mph

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq

cosine

step-by-step explanation: