Xiaoming is making cookies. Each batch of cookies uses3 eggs. If Xiaoming has 20 eggs, and assuming he has enough of the other ingredients to make the cookies what is the greatest number of batches that he can make ?

6

Step-by-step explanation:

3(1)=3       3(2)=6          3(3)=9      3(4)=12     3(5)=15

3(6)=18     3(7)=21         3(8)=24

3(6)=18 is closest to 20

so the greatest number of batches Xiaoming can make is 6.

1/3

step-by-step explanation:

to find this, you can divide 12 by 4 which is 3 or you can multiply 4 until you reach 12 (4x3=12). both should give you 3, meaning theres three times less bananas than there are oranges.

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)