Jamal drew the function below. Which explains whether or not his function is linear? On a coordinate plane, a line with negative slope goes through points (0, 1.5) and (1.5, 0).

"line" a straight line graph is always linear once the line isn't straight, it'll no longer be called a line and will never be linear anymore

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

98 points djdjsi zisksis sjsjsi sisksj sksjdj sksks sjsisj