In the given figure ab parallel cd find the value of x

Step-by-step explanation: x = 73°

Draw PQ through E and parallel to AB, CD

Have x = ∠QED + ∠QEB

because PQ // CD => ∠QED = 50°

AB // PQ => ∠QEB + 157° = 180°

=> ∠QEB = 180 - 157 = 23°

=> x = 23° + 50° = 73°

( PQ   is in the same direction as AB and CD )

angle efd = 130

180-50=130

angle ahe =23

180-157= 23

draw a imaginary line from h to f

this will create a triangle

now angle hfc = 90

90-50=40

now angle hfe =

90 - 23 = 67

therefore ,

x =

67+40+x=180

107 + x = 180

x = 180-107

x=73

found it xd it ok yt

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3