How to find vertex form with vertex: (3,6) and y intercept: 2

Step-by-step explanation:

The vertex form of  the equation of the parabola with vertex (h, k)  is:

f(x) = a(x - h)² + k

So for vertex (3, 6) it will be:

f(x) = a(x - 3)² + 6

y intercept: 2 means  f(0) = 2

f(0) = a(0 - 3)² + 6

2 = a(-3)² + 6

2 -6 = 9a + 6 -6

-4 = 9a

a = ⁻⁴/₉

Therefore:

The vertex form of quardatic function with vertex: (3,6) and y intercept: 2 is

                             f(x) = - ⁴/₉(x - 3)² + 6

8/k

step-by-step explanation:

system of linear equation

step-by-step explanation:

as given in the data

a= 20 , b= -12

let us suppose that it is a straight line equation

now we know the formula for the system of linear equation

b= ma + c )

here m is slope of a straight line which is equal to formula

m=   (ii)

and here c is a constant

now putting the value of a and b in equation (ii)

m=

m=

putting the value of a,b and m in equation (i) gives us

-12 = + c

-12=-12 + c

adding 12 to both sides

-12 +12 = -12 +12 +c

0 =c

or c=0

as the value of the constant is zero which gives us that it is a linear equation and this order pair satisfies the system of linear equations.