Three friends, A, B, and C form the vertices (corners) of a triangle on flat ground. Friend “A” is standing directly at the bottom of a sheer cliff. Directly above A, at
the top of the cliff, a fourth friend, “D”, is standing. The distance on the ground
between B and C is 400 m. The angle at “C” between A and B is 35º. The angle
at “B” between A and C is 27º. The angle of elevation from “C” to “D” at the top
of the cliff is 18° Find the angle formed at “D” between “B” and “C”.

asdasd

step-by-step explanation:

think about it deeply and passionately about this property

i am sorry

people grow faster than other people.

step-by-step explanation:

should you really be posting this isn't math boi.

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)