Mathematics, 13.11.2020 01:30 zay65307

A player located 18.6 ft from the basket launches a successful jump shot from a height of 10 ft (level with the rim of the basket), at an angle θ = 36º and an initial velocity of v = 25 ft/s. Find the change of distance Δs of the toss if the angle changes by an amount Δθ. Hint: Use the following fact derived from Newton's Laws: An object released at an angle θ with initial velocity v ft/s travels a total distance $s=\frac{1}{32} v^{2} sin(2\theta)$

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A player located 18.6 ft from the basket launches a successful jump shot from a height of 10 ft (lev...