Given z = 4 (cos (pi/ 2) + i sin (pi/2 ) ) , what is z3? a)12 (cosine (StartFraction pi Over 2 EndFraction) + I sine (StartFraction pi Over 2 EndFraction) )

b)64 (cosine (StartFraction pi Over 2 EndFraction) + I sine (StartFraction pi Over 2 EndFraction) )

c)12 (cosine (StartFraction 3 pi Over 2 EndFraction) + I sine (StartFraction 3 pi Over 2 EndFraction) )

d)64 (cosine (StartFraction 3 pi Over 2 EndFraction) + I sine (StartFraction 3 pi Over 2 EndFraction) )

cos(Pi) – isin(Pi)      (D)

Step-by-step explanation:

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x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

ok then what happened.