The function h(0) = -16t2 + vt + 10 gives the height of a platform diver above the water, in feet, t seconds after the diver leaves the platform with an initial velocity, v, in feet per second.
10 feet
On one dive, it takes the diver 1.42 seconds to reach the surface of the water.
• What was the initial velocity, V, in feet per second of the diver?
• After how much time, in seconds, since leaving the platform did the diver reach the same height as the platform?
What was the diver's maximum height, in feet, above the water?