Find the vertex and the equation for the axis of symmetry of the function f(x) = 4x^2 + 10x + 12. (Show work pls)

This is it and the work I did!

Step-by-step explanation:

Step by step solution :

STEP

1

:

Equation at the end of step 1

 (22x2 +  10x) +  12  = 0

STEP

2

:

STEP

3

:

Pulling out like terms

3.1     Pull out like factors :

  4x2 + 10x + 12  =   2 • (2x2 + 5x + 6)

Trying to factor by splitting the middle term

3.2     Factoring  2x2 + 5x + 6

The first term is,  2x2  its coefficient is  2 .

The middle term is,  +5x  its coefficient is  5 .

The last term, "the constant", is  +6

Step-1 : Multiply the coefficient of the first term by the constant   2 • 6 = 12

Step-2 : Find two factors of  12  whose sum equals the coefficient of the middle term, which is   5 .

     -12    +    -1    =    -13

     -6    +    -2    =    -8

     -4    +    -3    =    -7

     -3    +    -4    =    -7

     -2    +    -6    =    -8

     -1    +    -12    =    -13

     1    +    12    =    13

     2    +    6    =    8

     3    +    4    =    7

     4    +    3    =    7

     6    +    2    =    8

     12    +    1    =    13

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

answer: howdy

step-by-step explanation: