What is the center of the circle whose diameter has endpoints (18, -13) and (4, -3)?

Step-by-step explanation:

The center of the circle whose diameter has endpoints (18, -13) and (4, -3) will be the midpoint of the coordinates.

The ormua for calculating mid point is expressed as;

M(X,Y) ={(x21+x2/2, y1+y2/2}

X= x1+x2/2

Y = y1+y2/2

From the coordinates

x1 = 18 x2 = 4

X= 18+4/2

X = 22/2

X = 11

y1= -13, y2= -3

Y = -3-13/2

Y = -16/2

Y = -8

Hence the required centre will be at (11,-8)

y=-2.5x+12.5

step-by-step explanation:

5y=2x+10

y=0.4x+2

slope=-2.5

5=-2.5*3+b

b=12.5

cant

step-by-step explanation: there is no picture