A coin is tossed 5 times; find the probability of getting at least 1 tail. Would you consider this event likely to happen?

0.96875

Step-by-step explanation:

Probability of obtaining at least one tail on a toss of coin 5 times ;

P(success) in a coin toss = 1/2 = 0.5

Using the binomial distribution formula :

P(x) = nCx * p^x * (1 - p)^(n-x)

P(at least one tail) = 1 - p(0 tails)

P( 0 tails) = 5C0 * 0.5^0 * 0.5^(5-0)

= 1 * 1 * 0.03125

= 0.03125

P(at leat 1 tail) = 1 - 0.03125

P(atleast 1 tail) = 0.96875

the answer is 489

step-by-step explanation:

x equals 1

step-by-step explanation:

f(4)=f(×)

x=1