A stadium charges $75 for each seat in section A, $50 for each seat in section B, and $40 for section C. There are three times as many seats in section B as in section A. The revenue from selling odd 20,000 seats is 897,500. Write a system to represent the situation. A. b=3×c
a+b+c=20,000
75a+50b+40c=897,500

B. b=3×a
a+b+c=20,000
75a+50b+40c=897,500

C. a=3×b
a+b+c=20,000
40a+50b+75c=897,500

D. a=3×b
a+b+c=20,000
75a+50b+40c=897,500

B. b=3×a

a+b+c=20,000

75a+50b+40c=897,500

Step-by-step explanation:

A stadium charges

$75 for each seat in section A

$50 for each seat in section B

$40 for section C.

There are three times as many seats in section B as in section A.

a = 3× b

The revenue from selling odd 20,000 seats is 897,500.

a + b + c = 20,000 seats

Hence,

$75 × a + $50 × b + $40 × c = 897,500

75a + 50b + 40c = 897,500

Hence, the system of equations is :

B. b=3×a

a+b+c=20,000

75a+50b+40c=897,500

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11 -1> 1 -1+ a

-12 > a

answer: 8 years

step-by-step explanation:

the explanation is that in 8 years the child will be 20 and in 8 years the father will be 40 and 20 is half of 40.