Ross has a model truck. It has a scale of 1 inch for every 32 inches on a real-sized truck. He wants to build a garage for the model at the same scale. Given that the garage for a real-sized truck is 12 feet wide, how wide should his model garage be?

Answer in decimal form:  4.5 inches

Answer as a mixed number = 4 & 1/2 inches

Explanation:

" It has a scale of 1 inch for every 32 inches on a real-sized truck" means the the scale is 1:32

Put another way, the real life width is 32 times greater than the scale model.

So we can form the equation

y = 32x

where x is the scale model width and y is the actual real life width.

The garage in the real world is 12 feet wide, or 12*12 = 144 inches wide.

Plug y = 144 into the equation and solve for x

y = 32x

32x = y

32x = 144

x = 144/32

x = 4.5

His scale model garage must be 4.5 inches wide

4.5 inches = 4 & 1/2 inches = 4 and a half inches

answer: x

step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2