Which statement is true about figures ABCD and A'B'C'D?

Step-by-step explanation:

To understand the transformation better we will take a point B first.

Coordinates of B → (3, 0)

When we rotate this point by 180° counterclockwise about the origin, rule to be followed,

(x, y) → (-x, -y)

By this rule, coordinates of B'' will be,

B(3, 0) → B''(-3, 0)

Now we translate the point B by 2 units right.

Rule for the translation is,

(x, y) → [(x + 2), 0]

Following this rule,

B''(-3, 0) → B'[(-3+2), 0]

             → B'(-1, 0)

We can conclude with the statement, "Figure ABCD was rotated by 180° about the origin followed by the translation of 2 units to the right" to get the new figure A'B'C'D' similar to pre-image ABCD.

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560

answer is 33

step-by-step explanation: