Write an equation in standard form of the line that passes through the given point and the given slope. (-9, -4); m = -1/3

First, we must determine b using slope-intercept form*, the given point, and the given slope.

Second, we need to set up the equation of the line in slope-intercept form.

Third, we convert the above equation to STANDARD FORM**.

We now have our equation:

*Slope-intercept form: y = mx + b

**Standard form: ax + by = c

step-by-step explanation:

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."