Which term of the series 2187,729,243...is 1/9

Step-by-step explanation:

Givens

a = 2187

r = 1/3

L = 1/9

what is n

Formula

L = a*r^(n-1)

1/9 = 2187 * (1/3)^(n-1)

1/(9 * 2187) = (1/3)^(n - 1)

1/19683 = (1/3)^(n - 1)

You need to break 19683 down into its prime factors.

19683 = 3* 729

19683 = 3 * 3 * 243

19683 = 3 * 3 * 3 * 81

81 = 3^4 so there are 4 more threes in the breakdown.

19683 = 3 * 3 * 3 * 3 * 3 * 3 * 3

1/19683 = 1/(3)^(7-1)

1/9 is the 6th term in the series.

by definition, an arc subtended by a central angle of some given measure has the same measure. so .

let x be the money she spent so that she can earn the free t-shirt.

since, she already spent $112.49

⇒

also, as per the statement: jennifer must spend $250 or more in order to qualify for a free t-shirt at the store.

then,

we have an inequality i.,e

subtract 112.49 from both sides we get;

therefore, $137. 51 more money does jennifer need to spend so that she can earn the free t-shirt