Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = t2 + 35, y = ln(t2 + 35), z = t; (6, ln(36), 1)

Attached below is the detailed solution

answer : x(t), y(t), z(t) = ( 6 + t/6,  In (36) + t/18, 1 + t )

Step-by-step explanation:

x =  , y = In(t^2 + 35 ),  Z = t;(6, ln(36), 1)

Determine the parametric equations for the tangent line to the curve with the above given parametric equations

attached below is the detailed solution

you ignore the remainder, therefore the answer is y = x+2

step-by-step explanation:

you have to divide the denominator by the numerator. you can use synthetic division or long division.

[-5] .     1 .     7 .     11

x + 2 + 1/x+5